C#保留小数位数的方法集锦
2008-07-19 22:07
1.System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo(); provider.NumberDecimalDigits =intDecLength; //要設定的小數位數 double strCashAmt=Convert.ToDouble(this.txtCashAmt.Text); //先把控件內的值轉成double
this.txtCashAmt.Text = strCashAmt.ToString("N",provider); //再利用ToString函數格式化小數位數
2.保留N位,四舍五入 .
decimal d= decimal.Round(decimal.Parse("0.55555"),2);
3.保留N位四舍五入
Math.Round(0.55555,2)
4,保留N位四舍五入 double dbdata = 0.55555; string str1 = dbdata.ToString("f2");//fN 保留N位，四舍五入
5.保留N位四舍五入
string result = String.Format("{0:N2}", 0.55555);//2位
string result = String.Format("{0:N3}", 0.55555);//3位
6. 保留N位四舍五入
double s=0.55555; result=s.ToString("#0.00");//点后面几个0就保留几位
C#下如果显示保留小数位数，及百分号的解决方法:
1、用NumberFormatInfo类来解决: System.Globalization.NumberFormatInfo provider = new System.Globalization.NumberFormatInfo();
provider.PercentDecimalDigits = 2;//小数点保留几位数. provider.PercentPositivePattern = 2;//百分号出现在何处. double result = (double)1 / 3;//一定要用double类型. Response.Write(result.ToString("P", provider));
2、用toString方法.: public string getRate(double hcount, double task) { string rValue; string temp = "";
if (task == 0) { task = 1; }
double db = (hcount / task) * 100;
if (hcount >= task) { rValue = "100%"; } else { rValue = db.ToString("#0.#0") + "%"; } return rValue; }
string str1 = String.Format("{0:N1}",56789); //result: 56,789.0 string str2 = String.Format("{0:N2}",56789); //result: 56,789.00 string str3 = String.Format("{0:N3}",56789); //result: 56,789.000 string str8 = String.Format("{0:F1}",56789); //result: 56789.0 string str9 = String.Format("{0:F2}",56789); //result: 56789.00 string str11 =(56789 / 100.0).ToString("#.##"); //result: 567.89 string str12 =(56789 / 100).ToString("#.##"); //result: 567
