LeetCode_数位枚举_困难_233.数字 1 的个数

星许辰发布时间：2022-07-30 09:48:49 ，浏览量：0

1.题目
2.思路
3.代码实现（Java）

1.题目

给定一个整数 n，计算所有小于等于 n 的非负整数中数字 1 出现的个数。

示例 1：输入：n = 13 输出：6，对应的整数为 1、10、11、12、13（整数 11 中有 2 个 1）

示例 2：输入：n = 0 输出：0

提示： 0

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LeetCode_数位枚举_困难_233.数字 1 的个数

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