PAT (Advanced Level) Practice 题目集合（1001 ~ 1050）（正在更新）

1001 A+B Format (20 分)

题目大意：计算a+b，结果按照西方的那种写数字的方式输出，从三个数一个逗号那种。

#include
using namespace std;

int main()
{
	int a, b, c;
	string s, ans, flag;
	cin >> a >> b;
	c = a + b;
	if (c  kb;
	for (int i = 0;i > a >> b;
		c2[a] = b;
		mn = min (a, mn), mx = max (a, mx);
	}
	
	for (int i = mn;i  e >> c, ita.push_back ({e, c});
	cin >> kb;
	for (int i = 0;i > e >> c, itb.push_back ({e, c});
	
	sort (ita.begin (), ita.end (), cmp);
	sort (itb.begin (), itb.end (), cmp);
	
	for (int i = 0, j = 0;i  t;
	
	for (int i = 0;i > g[i];
	
	while (m --) {
		cin >> a >> b >> c;
		e[a][b] = c;
		e[b][a] = c;
	}

	Dijkstra ();
	
	cout  id >> k;
		while (k --) cin >> child, a[id].push_back (child), st[child] = 1;
	}	
	
	for (int i = 1;i  b;
	LL m = n;
	while (m) {
		a[cnt ++] = m % b;
		m /= b;
	}	
	
	if (check ()) puts ("Yes");
	else puts ("No");
	
	for (int i = cnt-1, flag = 0;i >= 0;i --) {
		if (flag) cout