一个 Servlet 如何处理多种请求? 1.使用后缀匹配模式 2.在 service 方法中获取请求资源路径,分析资源路径来决定作何处理
示例代码如下:
package priv.lwx.javaex.web_demo_02.web.servlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
* 使用Servlet处理多种请求
*
* @author liaowenxiong
* @date 2021/12/23 12:00
*/
public class ServletDemo02 extends HttpServlet {
public void service(HttpServletRequest request, HttpServletResponse response) {
String uri = request.getRequestURI();
String path = uri.substring(uri.lastIndexOf("/"), uri.lastIndexOf("."));
System.out.println("uri: " + uri);
System.out.println("path: " + path);
if (path.equals("/list")) {
System.out.println("list...");
} else if (path.equals("/del")) {
System.out.println("del...");
} else if (path.equals("/add")) {
System.out.println("add...");
}
}
}
web.xml 的配置如下:
demo02
priv.lwx.javaex.web_demo_02.web.servlet.ServletDemo02
demo02
*.do