一、LeetCode之两数之和
力扣
public class TwoSum {
/**
* 通过双重循环遍历数组中所有元素的两两组合
* 当出现符合的和时返回两个元素的下标
* @param nums
* @param target
* @return
*/
public static int[] twoSum1(int[] nums, int target) {
for (int i = 0; i < nums.length; i++) {
for (int j = i + 1; j< nums.length; j++) {
if (target - nums[i] == nums[j]) {
return new int[]{i, j};
}
}
}
return null;
}
//哈希
public static int[] twoSum2(int[] nums, int target) {
HashMap map = new HashMap();
for (int i = 0; i < nums.length; i++) {
int partnerNumber = target - nums[i];
if (map.containsKey(partnerNumber)) {
return new int[]{map.get(partnerNumber), i};
}
map.put(nums[i], i);
//map K值 V下标
// 2 0
}
return null;
}
public static void main(String[] args) {
int[] nums = new int[]{2, 7, 11, 15};
int target = 22;
int[] myIndex = twoSum2(nums, target);
System.out.println(Arrays.toString(myIndex));
}
}
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