迷你语法分析器
给定一个字符串 s 表示一个整数嵌套列表,实现一个解析它的语法分析器并返回解析的结果 NestedInteger 。 列表中的每个元素只可能是整数或整数嵌套列表 来源:力扣(LeetCode)
官方代码# """
# This is the interface that allows for creating nested lists.
# You should not implement it, or speculate about its implementation
# """
#class NestedInteger:
# def __init__(self, value=None):
# """
# If value is not specified, initializes an empty list.
# Otherwise initializes a single integer equal to value.
# """
#
# def isInteger(self):
# """
# @return True if this NestedInteger holds a single integer, rather than a nested list.
# :rtype bool
# """
#
# def add(self, elem):
# """
# Set this NestedInteger to hold a nested list and adds a nested integer elem to it.
# :rtype void
# """
#
# def setInteger(self, value):
# """
# Set this NestedInteger to hold a single integer equal to value.
# :rtype void
# """
#
# def getInteger(self):
# """
# @return the single integer that this NestedInteger holds, if it holds a single integer
# Return None if this NestedInteger holds a nested list
# :rtype int
# """
#
# def getList(self):
# """
# @return the nested list that this NestedInteger holds, if it holds a nested list
# Return None if this NestedInteger holds a single integer
# :rtype List[NestedInteger]
# """
class Solution:
def deserialize(self, s: str) -> NestedInteger:
index = 0
def dfs() -> NestedInteger:
nonlocal index
if s[index] == '[':
index += 1
ni = NestedInteger()
while s[index] != ']':
ni.add(dfs())
if s[index] == ',':
index += 1
index += 1
return ni
else:
negative = False
if s[index] == '-':
negative = True
index += 1
num = 0
while index
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