给你一个由 '1'
(陆地)和 '0'
(水)组成的的二维网格,请你计算网格中岛屿的数量。
岛屿总是被水包围,并且每座岛屿只能由水平方向和/或竖直方向上相邻的陆地连接形成。
此外,你可以假设该网格的四条边均被水包围。
示例 1:
输入:grid = [ ["1","1","1","1","0"], ["1","1","0","1","0"], ["1","1","0","0","0"], ["0","0","0","0","0"] ] 输出:1
示例 2:
输入:grid = [ ["1","1","0","0","0"], ["1","1","0","0","0"], ["0","0","1","0","0"], ["0","0","0","1","1"] ] 输出:3
示例代码:
class Solution:
def numIslands(self, grid: List[List[str]]) -> int:
row, col = len(grid), len(grid[0])
ret = 0
def dfs(x, y):
grid[x][y] = '0'
lst = [[1,0], [-1, 0], [0, 1], [0, -1]]
for i in lst:
nx, ny = x + i[0], y + i[1]
if 0
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